Help Me Solve the torque problem Please
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Posted by: robertedelong ®

08/26/2006, 19:48:58
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re: wind generators; the new models I'm looking at are the low rpm (25-100 rpm)
Permanent magnet; direct drive; regarding the generator; What is the torque required to drive these generators? Lets consider two outputs; 350KW and 1 MW; wind sites usually do not reveal torque or horsepower; To simplify what I'm asking for: how much torque (from say an electric motor or a diesel engine)would be needed to drive a 350 KW generator at maximum load. The same for a 1 MW generator. Forget about starting torque, hysteresis,friction or cogging. I'm asking maximum rating needed. Let's ballpark this if that's OK with you.Thanks for any help you can provide







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Re: Help Me Solve the torque problem Please
Re: Help Me Solve the torque problem Please -- robertedelong Post Reply Top of thread Forum
Posted by: Zip ®

08/31/2006, 01:31:07
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Most gensets run @ 1800 R.P.M. I calculate 469 H.P. for
350 K.W. With 1368 ft.lbs. Ballpark!
.746 K.W. per H.P.. H.P.x 5252
----------- = lb.ft. Torque
R.P.M.
Cheers
Z





Zip


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Re: Help Me Solve the torque problem Please
Re: Help Me Solve the torque problem Please -- robertedelong Post Reply Top of thread Forum
Posted by: zekeman ®

08/28/2006, 09:52:09
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torque*rpm*2pi/33000=horsepower
.746KW=1Horsepower
You need to know RPM to get the torque.







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Re: Help Me Solve the torque problem Please
Re: Help Me Solve the torque problem Please -- robertedelong Post Reply Top of thread Forum
Posted by: randykimball ®
Barney
08/27/2006, 13:15:28
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1 KW = 1.36 metric HP

so...

350 KW = 475.87 mHP
1000 KW (1 MW) = 1,359.62 mHP


of a slight difference
1 KW = 1.34 electric HP
If you stick with the mHP you will build in a fudge factor.

Unfortunately these do not directly convert to torque.





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Modified by randykimball at Sun, Aug 27, 2006, 13:22:02


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