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Hydraulic wheel motors | |||
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Posted by: john-oden ® 12/26/2005, 00:33:51 Author Profile eMail author Edit |
I am busy building a front end loader which when full weighs 14000 kg, the speed on a flat surface is 10km/h and on an incline of 15 deg it must run at 4km/h. The wheels are rubber inflated with a diameter of 1135mm. Each wheel will have a hydraulic wheel motor. The machine will be driven by a 65kw diesel engine which will drive the hydraulic pump. The diesel engine can run at a constant speed of 1500-2500 rpm.
What torque will I need per wheel.With this information will I be able to select a hydraulic wheel motor. Thanks John Oden |
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Re: Hydraulic wheel motors -- john-oden | Post Reply | Top of thread | Forum |
Posted by: randykimball ® 12/26/2005, 17:46:50 Author Profile eMail author Edit |
John,
You may want to tell the forum group if it is ok to put a reduction gear at the wheel, and perhaps what reduction is allowed. This will greatly effect the resultant torque. The worst suggestion of your lifetime may be the catalyst to the grandest idea of the century, never let suggestions go unsaid nor fail to listen to them. |
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Re: Hydraulic wheel motors | |||
Re: Re: Hydraulic wheel motors -- randykimball | Post Reply | Top of thread | Forum |
Posted by: jvan ® 01/04/2006, 12:08:22 Author Profile eMail author Edit |
John, You may have a problem, especialy with the gradeability.
If we ignore air resistance because of your low speed; tractive effort is the sum of Rolling Resistance and gradeability. I am an old guy used to imperial so here goes. GVW= 14000 kg or 30865 lbs Speed is 10km/h or 6.2 mph Rolling Radius (r) is 1135 mm dia. or 44.68" dia so 22.34" 15 degree grade is 26.8 % grade (STEEP) Road Rolling Resistance= (GVW x R (a factor, 20 lbs for poor concrete))/ 1000 so
Grade Resistance = .01 x GVW x %grade so
Tractive Effort= (Torque x 12)/r; solving for Torque
Speed (mph) = (RPM x r) /168 (a constant) solving for RPM
Fluid Motor Torque in in/lbs T= (Pressure x displacement (cubic inches))/ 2 Pi so Displacement = (T x 2Pi) / Pressure Assuming a 3000 PSI system with 2000 psi available at the drive motors. Displacement = 156 cubic inches. Any gear ratio will change this displacement, but the flow will just increase, power is power. Drive flow = (motor RPM x Displacement)/ 231 cubic in. per gallon = 31 GPM per motor.
The large torque required is due to the high gradeability, to solve your problem you are probably going to have to go to a two speed motor ( higher torque on the grade) or get tricky with a series parallel circuit on the motors, series for high torque, parallel for high speed.
If you have any questions, I will be happy to help if I can.
Modified by jvan at Wed, Jan 04, 2006, 16:55:37 |
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Re: Re: Hydraulic wheel motors -- jvan | Post Reply | Top of thread | Forum |
Posted by: Dan wilson ® 08/31/2007, 17:00:23 Author Profile eMail author Edit |
jvan,
would it be fesible to build the following with hyd wheel motors? A 6 wheel amphibious atv, with 4 of the wheels steering. not a skid steer type. I want, say 3 wheels, or better, 2 wheels to pull the load
What do you think? Thanks, Dan
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